jiapengyu
12 lines
237 B
JavaScript
12 lines
237 B
JavaScript
exports = function(num) {
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var boundary = Math.floor(Math.sqrt(num));
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for (var i = 2; i <= boundary; i++) {
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if (num % i === 0) {
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return false;
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}
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}
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return num >= 2;
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};
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module.exports = exports;
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